What Adam said; something like:

SELECT custid, (select count(*) FROM ordertable where TTL=X), (select count(*) FROM ordertable where TTL=Y)
FROM ordertable
order by custid;


On Thu, Mar 24, 2016 at 9:21 AM, Adam Thompson <athompso@athompso.net> wrote:
Subqueries:
SELECT (SELECT ...), (SELECT ...) FROM ...

If they don't work, upgrade to a newer version of MariaDB. (If this is the customer I assume it is, use RackSpace's IUS repo to upgrade).

Alternately, create two VIEWs, one for each aggregate count, and OUTER JOIN them.
-Adam


On March 24, 2016 9:16:31 AM CDT, Trevor Cordes <trevor@tecnopolis.ca> wrote:
Can anyone help me figure out how to do this in SQL (MySQL)?

(pseudo-code giving you the gist):

SELECT custid, (count orders where ttl=X), (count orders where ttl=Y)
FROM ordertable
GROUP BY custid;


I basically want to count two different things based on two different
wheres. If I put in a where clause then I select either the X or the Y
but I can't seem to get both in such a way I can count the X's and Y's. I
tried thinking about unions but couldn't make it work. I want to do this
all in 1 query as I want the sorted union of all custid's (X and Y).

P.S. ordertable has/can have multiple entries for each custid.

Ideas are appreciated!


Roundtable mailing list
Roundtable@muug.mb.ca
http://www.muug.mb.ca/mailman/listinfo/roundtable

--
Sent from my Android device with K-9 Mail. Please excuse my brevity.

_______________________________________________
Roundtable mailing list
Roundtable@muug.mb.ca
http://www.muug.mb.ca/mailman/listinfo/roundtable




--
John Lange
www.johnlange.ca